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16x^2-59x=20
We move all terms to the left:
16x^2-59x-(20)=0
a = 16; b = -59; c = -20;
Δ = b2-4ac
Δ = -592-4·16·(-20)
Δ = 4761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4761}=69$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-59)-69}{2*16}=\frac{-10}{32} =-5/16 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-59)+69}{2*16}=\frac{128}{32} =4 $
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